30=16t^2+24t+30

Solution for 30=16t^2+24t+30 equation:

30=16t^2+24t+30

We move all terms to the left:

30-(16t^2+24t+30)=0

We get rid of parentheses

-16t^2-24t-30+30=0

We add all the numbers together, and all the variables

-16t^2-24t=0

a = -16; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·(-16)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*-16}=\frac{48}{-32}
=-1+1/2
$